derivatives are not evaluated in evaluation of components

Question

Hi, I wanted to compute the metric of AdS{d+1} through its embedding in \mathbb{R}^{d+2}. When evaluating the components of the induced metric as below, it ends up with components that still contain derivatives, i.e. things like \partial{\phi}{\cos{\phi}}, whereas if I compute the derivative directly, e.g.

ll :=\partial_{\phi}{\cos{\phi}}
evaluate(ll);

it evaluates it correctly. So how do I evaluate these derivative if I have all the component together in an expression?

{t,\rho,\phi}::Coordinate;
{A,B}::Indices(higher,values={0,1,2,3}, position=fixed);
{\mu, \nu, \sigma, \kappa,\alpha,\beta,\gamma}::Indices(lower,values={t,\rho,\phi}, position=fixed);
X^{A}::Depends(t,\rho,\phi);

\partial{#}::PartialDerivative;

X^{A}::Depends(t,\rho,\phi,\partial_{\nu}{#});
g_{A B}::Metric(higher).
g^{A B}::InverseMetric(higher).

G_{\mu \nu}::Metric(lower).
G^{\mu \nu}::InverseMetric(lower).


metricRdp2 := [
g_{0 2} = 0, g_{0 3} = 0, g_{0 4} = 0,
g_{0 1} = 0, g_{1 2} = 0, g_{1 3} = 0,g_{1 4} = 0,
g_{2 3} = 0,g_{2 4} = 0,g_{3 4}= 0,  g_{4 4} = -1, g_{0 0} = -1, 
g_{1 1} = 1, g_{2 2} = 1, g_{3 3} = -1];

global2 := [ X^{0} = R \cosh{\rho} \cos{t}, 
X^{3} = R \cosh{\rho} \sin{t}, 
X^{1} = R \sinh{\rho} \sin{\phi},
X^{2} = R \sinh{\rho} \cos{\phi}];

cc := G_{\mu \nu} = \partial_{\mu}{X^{A}}\partial_{\nu}{X^{B}}g_{A B};

ex2 := G_{\mu \nu}:
substitute(ex2,cc);

evaluate(ex2)
canonicalise(ex2)
substitute(ex2,metricRdp2)
substitute(ex2,global2)
unwrap(ex2)
collect_factors(ex2);