question about untrace&ImaginaryI

Question

when I combine untrace and ImaginaryI, the property ImaginaryI will lose efficacy, this is a example

i::ImaginaryI;
A::ImplicitIndex.
tr{#}::Trace.
ex:= i tr(i A);
untrace(_);

there seems to be some bugs.

substitute(_,$i i->-1$);

is also not valid.

Answer 1

Now fixed in master on github.

Comments

Thanks. It works.