HI Folks,

I have an expression such as

```
foo := t0 A + t2 B + t13 C;
```

and I like to easily replace each of the t* scalars with 1. So my target result is

```
foo := A + B + C;
```

Using something like

```
substitute (foo, $t? -> 1$)
```

fails because it replaces all objects with 1, not just the scalars. Is there a simple way to do this properly for any expression like the above, no matter how many terms?

Cheers,

Leo